{ "cells": [ { "cell_type": "markdown", "metadata": {}, "source": [ "# 7.32 NPSH Available Calculation" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "Given that a pump is located 30 feet above sea level, has a NPSHr of 20' at a flow rate of 400 gpm, and is fed by a tank of 60 deg F water with a surface pressure of 5 psig and a liquid level 25' below the suction of the pump.\n", "\n", "The head losses in the suction pipeline are 6'.\n", "\n", "Find the NPSH available and compare it to the NPSHr. A NPSHr margin ratio is required." ] }, { "cell_type": "code", "execution_count": 1, "metadata": {}, "outputs": [ { "data": { "text/html": [ "13.887316780096477 foot" ], "text/latex": [ "$13.887316780096477\\ \\mathrm{foot}$" ], "text/plain": [ "13.887316780096477 " ] }, "execution_count": 1, "metadata": {}, "output_type": "execute_result" } ], "source": [ "from fluids.units import *\n", "rho = 62.364*u.lb/u.ft**3\n", "P_tank = 5*u.psi + 1*u.atm\n", "Psat = 0.256*u.psi\n", "H_tank = 5*u.foot\n", "H_pipe = 30*u.foot\n", "dH = H_pipe - H_tank\n", "\n", "head_loss = 6*u.foot\n", "\n", "NPSHa = ((P_tank-Psat)/rho/u.gravity) - dH - head_loss\n", "(NPSHa).to(u.foot)" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "The NPSHa is beneath the NPSHr. The requested pressure can be calculated as follows:" ] }, { "cell_type": "code", "execution_count": 2, "metadata": {}, "outputs": [ { "data": { "text/html": [ "26.0 foot" ], "text/latex": [ "$26.0\\ \\mathrm{foot}$" ], "text/plain": [ "26.0 " ] }, "execution_count": 2, "metadata": {}, "output_type": "execute_result" } ], "source": [ "20*u.foot*1.3" ] } ], "metadata": { "language_info": { "name": "python" } }, "nbformat": 4, "nbformat_minor": 1 }